Motion mathematical part2 Problem 1:A ball is thrown vertically upward with a speed of 44 m/s from the ground. At what time will the ball be 90 m above the ground?Solution:
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Motion Mathematical physicsStarting from rest a car speed of 45 km/h in 2 minutes. Find the acceleration and the distance transversed by this time.Solution:Here, initial velocity u = 0time t = 2 minutes = 120 second final velocity v = 45 km/hacceleration a =? distance S =?
We know, v = u + at^2⇒ a = (v - u) /t^2⇒ a = (12.5 - 0)/120^2⇒ a = 0.104 ms^-2Now, S = ut + (1/2)at^2 = 0×120 + (1/2)×0.104 ×120^2 = 0 + 748.8 m = 748.8 m acceleration of the car is 0.104 ms^-2an…