Motion Mathematical physics

Starting from rest a car speed of 45 km/h in 2 minutes. Find the acceleration and the distance transversed by this time.

Solution:

Here, initial velocity u = 0

time t = 2 minutes = 120 second

final velocity v = 45 km/h

acceleration a =?

distance S =?

We know, v = u + at^2

⇒ a = (v - u) /t^2

⇒ a = (12.5 - 0)/120^2

⇒ a = 0.104 ms^-2

Now,

S = ut + (1/2)at^2

= 0×120 + (1/2)×0.104 ×120^2

= 0 + 748.8 m

= 748.8 m

acceleration of the car is 0.104 ms^-2

and the distance transversed by this time is 748.8 m

Motion mathematical part1